Maths task : Compensation with Multiplication
Here a example:
34 x 3=
for example we have these numbers and our number 34
is not complete we must add up to arrive at a compensation number as in this case 40
34+6=40
We add 34 and the number of missing numbers until we reach 40, that is 6
40x3=12o
so we take the result and multiply it by 3, which is the number that
our current in your multiplication has
3x6=18
then we take the number of your multiplication, that is 3 and the
one that added the number 34, which is 6
120-18=102
Now since we have the result we must take the result and subtract
it with the previous result that you added.
My Maths Exercises :
1. 28 x 5= 140 3. 80 x 3= 240
28 + 2=30 80 + 10=90
30x5= 150 90x3=270
5x2=10 3x10=30
150-10=140 270-30=240
2. 45 x 6= 270 4. 24 x 7= 168
45+5= 50 24+6=30
50x6=300 30x7=210
5x6=30 7x6=42
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